Question

if the motion of a body of mass 2 kg is described by y=10t-5t square then what is the force acting on it

Answer 1

mass = 2kg
we need to find acceleration now.

v(velocity) = ds/dt which is the differentiation of position w.r.t time
v= 10-5t

now acceleration = dv/dt which is the differentiation of velocity w.r.t time
acceleration = 5

F = m x a
= 2 x 5
= 10