if the mth term of an A.P is 1/n and the nth term is 1/m. show that the sum of mnth term is 1/2(mn+1)
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Step-by-step explanation:
let nth term be 1st term = a=1/n
mth term be 2nd= a+d=1/m
the last term is 2nd term
since sum = 2/2(2a+(2-1)d)
1/n+1/m
LCM= nm
(n+m)/nm
sum=1/n+1/m
there are loops but if some one can clear them please do it
there are hints here
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Jai Shri Ram!!!!!!!
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