If the mth term of an A.P. is (2m +1), then the sum of its first three terms is
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m th term = 2m + 1
=> a + (m - 1) d = 2m + 1
=> a + (m - 1) d = 3 + (m - 1)2
comparing LHS and RHS
a = 3 and d = 2
therefore S3
= 3/2 { 2a + (3-1)d }
= 3/2 ( 2 x 3 + 2 x 2 )
= 3/2 x 10
= 15
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