If the mth term of an ap is 1/n and nth term is 1/m,show that (mn) th term is 1
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1/n=a+(m−1)d
1/m=a+(n−1)d
Subtracting
m−n/mn=(m−n)d
d=1/mn
substituting the value of d equation 1
a=1/n−(m−1)/mn
Tmn=a+(mn−1)d
=a+(mn−1)/mn
=1/n−(m−1)/mn+(mn−1)/mn
=1/n+(n−1)/n
=(n−1+1)/n
=n/n
=1
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