Question

If the mth term of an AP IS 1÷n and nth term is 1÷m ,then show that the sum of mn term is 1÷2 (mn+1).

Answer 1

Attachments will help you (hope so) ^__^...

Answer 2

Answer:

Therefore, Am = a+ (m-1)d=1/n ….(i)

An = a+(n-1)d=1/m ….(ii)

Subtracting equation (ii) from (i)

d[(m-1)-(n-1)] = 1/n-1/m,

d(m-n) = (m-n)/mn,

d = 1/mn ….(iii)

Substituting equation (iii) in (i)

a+(m-1)/mn = 1/n,

a = 1/n[1-(m-1)/m],

a = 1/mn ….(iv)

Now Amn i.e the mnth term of AP = a+(mn-1)d,

Step-by-step explanation: