Math, asked by ajaymalik3006, 3 days ago

if the multiplication of 1701 and 1 # 6 is completely divisible by 28 then value of # ?

(a) 6
(b) 4
(c) 2
(d) 1

Answers

Answered by shagunpathak

0

Answer:

(d) 1

Step-by-step explanation:

1701x116 = 197316

197316/28 = 7047

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