Question

If the n sum of a certain number of terms starting from first term of an A.P. is 25,22,19,.. is 116. Find the last term.

Answer 1

Last term = 4.

Given:

If the n sum of a certain number of terms starting from first term of an A.P. is 25,22,19,.. is 116.

To find:

Last term.

Formula used:

Sum of n terms in arithmetic prorogation =  (2A+(n-1)×d)

$n^t^h$ term = a+(n-1)×d

                       Where A = First term

                                   L = last term

                                   d = common difference

Explanation:

d =  common difference = 22-25 = - 3

Sum of n terms in arithmetic prorogation =  (2A+(n-1)×d)

                                                               116 =  (50 +(n-1)×(-3) )

                                                                 n = 8

$n^t^h$  term = a+(n-1)×d

               = 22+(8-1)×(-3)

$n^t^h$  term = 4.

Therefore, the last term is 4.

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