If the nitrogen atom had electronic configuration 1s⁷ it would have
energy lower than that of the normal ground state configuration
1s² 2s² 2p³ because the electrons would be closer to the nucleus. Yet
1s⁷ is not observed. It violates
(a) Heisenberg’s uncertainty principle
(b) Hund’s rule
(c) Pauli exclusion principle
(d) Bohr postulate of stationary orbits
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(c) Pauli exclusion principle
Explanation:
As per Pauli's exclusion principle, no two electrons in the same atom can have all the four quantum numbers equal or an orbital cannot contain more than two electrons and it can accommodate two electrons only when their directions of spins are opposite.
Option C is the answer.
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