Question

If the no. 357*25* is divisible by 3 and 5
the missing digit in the unit's place & the
thousands place respectively are ?

solution please​

Answer 1

Answer:

0 and 2

Step-by-step explanation:

Let the unit's place be x and the thousand's place be y.

Then, 357y25x is divisible by 5 only when x = 0 or x = 5

Also, this number is divisible by 3 only when sum of its digits is divisible by 3

So, (22 + x + y) must be divisible by 3

∴ x + y = 2

Taking x = 0, we get y = 2

So, the unit place = 0 and thousand's place = 2

Mark me brainliest :)))

Answer 2

Answer:

Pair as ones then thousands digits

(0, 2), (0, 5), (0, 8), (5, 0), (5, 3), (5, 6), (5, 9)

Step-by-step explanation:

See image given below...