Question

If the normal pushing force of 25 LBS is required to push a wheel chair on a level floor for

160 lbs patient, calculate the pushing force of the wheelchair carrying 160 LBS weight when the ramp

angle is 20 degrees.​

Answer 1

Explanation:

Given If the normal pushing force of 25 LBS is required to push a wheel chair on a level floor for 160 lbs patient, calculate the pushing force of the wheelchair carrying 160 LBS weight when the ramp angle is 20 degrees.

• Given Weight of patient and wheel chair is 160 lbs
• So the normal force = 160 lbs and the pushing force or frictional force = 25 lbs.
• Now coefficient of friction μ = frictional force / normal force
•                                                   = 25 / 160
•                                                   = 0.15625
• So on a 20 degree ramp there is decrease in normal force and so the gravitational force and frictional force down the ramp are  
•         Frictional force = μ x normal force.
•                                    = 0.15625 x 160 cos 20 degree
•                                    = 0.15625 x 160 x 0.93969
•                                    = 23.49 lbs
•         Gravitational force = 160 x sin 20 degree
•                                            = 0.342020 x 160
•                                            = 54.72 lbs
•     Therefore the total force or the net force required to push the chair will be  
•                                                 = Frictional force + Gravitational force
•                                                 = 23.49 + 54.72
•                                                 = 78.21 lbs
• So this means that the applied force is parallel to the ramp.

Reference link will be

https://brainly.in/question/15015480