Question

If the nth term in a pattern of numbers is 2n+3 then find its 10th term

Answer 1

Answer:

Answer : 

N/a

Solution : 

Tn=2n+3Tn=2n+3

⇒Tn−1=2(n−1)+3⇒Tn-1=2(n-1)+3

=2n−2+3=2n+1=2n-2+3=2n+1

∴Tn−Tn−1=(2n+3)−(2n+1)=2∴Tn-Tn-1=(2n+3)-(2n+1)=2

which does not depend on 'n'.

Therefore, the difference of two consecutive terms is constant.

⇒⇒ Given progression is an arithmetic progression.

Now, T10=2×10+3=23

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