Question

"If the nth term of a progression is (4-10) show that it is an AP. Find its
(1) first term, (ii) common difference, and (iii) 16th term.
​

Answer 1

Step-by-step explanation:

We have ,

Tn= 4n-10

→T1= 4-10=-6

T2=4×2-10=-2

T3= 4×3-10=2

T16=4×16-10=54

Hence , first term=-6;

common difference =T2-T1=-2+6=4

and , 16 th term =54

Answer 2

Refers to attachment ...!!☻☻