If the nth term of a progression.is(4b-10) , show that it is an AP. Find its (1) first term (2) common difference (3) 16 th term
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Answered by
7
The given term can be written as: (-6)+(n-1)4 → general term of Arithmetic Progression.
1. -6
2. 4
3. 54
1. -6
2. 4
3. 54
Answered by
13
Put b=1,2,3... We get first term (4-10)= -6
Second tem (4*2-10) = -2 , third term = ( 4*3-10)= 2 this shows that terms are in AP with a common difference of 4 ,
16th term = 4*16-10= 54
eshitarai16lk:
Thanks for answer
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