If the nth term of a sequence is 3n + 4 , find the sum of 8 terms of the sequence .
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aN = 3n + 4
If n = 1
aN = 3n + 4
a1 = 3 × 1 + 4
a1 = 3 + 4 = 7
If n = 2
aN = 3n + 4
a2 = 3 × 2 + 4 = 6 + 4 = 10
d = a2 - a1 = 10 - 7 = 3
S8 = n/2 [a + (n-1)d]
= 8/2 [7 + (8-1) × 3]
= 4 [7 + 7 × 3]
= 4 [7 + 21]
= 4 × 28
= 112
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