if the nth term of a sequence is given by an=3 - 4n , find the sum of the first sixteen terms of the sequence.
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Answered by
46
given
an=3-4n
a1=3-4=-1
a2=3-8=-5
common difference =(-5+1)=-4
now use formula
Sn=n/2 {2a+(n-1) d}
S16=16/2 {2 (-1)+(16-1)(-4)}
=8 (-2-60)=-8x62=-496
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an=3-4n
a1=3-4=-1
a2=3-8=-5
common difference =(-5+1)=-4
now use formula
Sn=n/2 {2a+(n-1) d}
S16=16/2 {2 (-1)+(16-1)(-4)}
=8 (-2-60)=-8x62=-496
please mark as brainliest
Answered by
0
Answer:
Step-by-step explanation:
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gdg
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hgfgfh
gdgdfh
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fhdgg
fdgh g
fdh gg
fdh gg
dfh g
gfdh g
gdfh g
gdfh g g
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