If the nth term of an A.P. -1, 4, 9, 14,..... is 129. Find the value of n and Sn
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AP : –1, 4, 9, 14, ..., 129
So, Tn = (–1) + (n–1)(5)
= –1 + 5n –5
= 5n – 6
For, Tn = 129 = 5n–6
n = 27
Here, Sn = n/2 (T1+Tn) = n/2(Tn – 1)
= 27/2 (–1+129)
= 27 (64)
S_(27) = 1728
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