if the nth term of an A.P. is (2n+1), find the sum of the first n terms of the A.p.
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The formula of Sum is n/2(a+l)
So the sum of first n terms is n/2(3+2n+1)
The sum of first n terms is n^2 + 2n
So the sum of first n terms is n/2(3+2n+1)
The sum of first n terms is n^2 + 2n
Anonymous:
Can u explain plz?
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