If the nth term of an
a.P. Is 2n + 1, then the sum of first n terms of the
a.P. Is
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Step-by-step explanation:
here 2n+1 is nth term of AP,
to find out the AP, consider n as 1,2,3
So 2*1+1=3,2*2+1=5,2*3+1=7,
now a=3, d=2 ( since 7-5 and 5-3 both are equal to 2)
to find the nth term
S= n/2[a+l]
S= n/2[3+2n+1]
S= n/2[4+2n]
S=n[2+n]
Therefore S = n2+2n
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