Question

If the nth term of an A.P is (2n+i), find the sun
of the first n terms of the A.P​

Answer 1

Answer:

The sum of n terms in an AP is given by

s= n/2(2a+(n-1)d)

where

s = sum of progression

n = number of terms

a = value of first term

d = difference between 2 terms

now, the first term in your question is 3 (2 x 1 + 1)

so, a = 3

second term is 5

third is 7, like that

so d = 2

Therefore, the sum of first n terms of the AP will be

n/2 [2 x 3 + (n-1) 2]

simplifying, we get the sum as

n [3+n-1]

n (n+2)

Step-by-step explanation:

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Answer 2

Answer:

The sum of n terms in an AP is given by

s= n/2(2a+(n-1)d)

where

s = sum of progression

n = number of terms

a = value of first term

d = difference between 2 terms

now, the first term in your question is 3 (2 x 1 + 1)

so, a = 3

second term is 5

third is 7, like that

so d = 2

Therefore, the sum of first n terms of the AP will be

n/2 [2 x 3 + (n-1) 2]

simplifying, we get the sum as

n [3+n-1]

n (n+2)