If the nth term of an A.P; is an = 3+2n then S24
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Therefore.,
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- nth term of AP is an = 3 + 2n
- sum of 24 terms.
Putting n = 1 in eq.(i)
putting n = 2 in eq.(i)
putting n = 3 in eq.(i)
So, we get an AP :- 5 , 7 ,9
In which ,
- first term (a) = 5
- common difference (d) = 7-5 = 2
So,
»★ Sum of 24 terms = 672.
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