if the nth term of an AP is (2n-1) , then find sum of its first three terms
Answers
Answered by
5
An=(2n-1),
then
A1=(2×1-1)=1=first term(a),
A2=(2×2-1)=3,
A3=(2×3-1)=5,
then
d=3-1=2,
therefore
Sum of first three terms=1+3+5=9
then
A1=(2×1-1)=1=first term(a),
A2=(2×2-1)=3,
A3=(2×3-1)=5,
then
d=3-1=2,
therefore
Sum of first three terms=1+3+5=9
Answered by
1
Answer:
Step-by-step explanation:
an= 2n-1 if n=1 awill be equal to 1 if n=2 second term=3 d=2 therefore substituting values in formula we get sum of three terms as 9
Similar questions