if the nth term of an ap is 2n+1 then find the sum of the first three terms
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Answer:
A1 = 2(1)+1 ==> 2
A2 = 2(2)+1 ==> 5
SO, D = A2-A1 ===> 5-2 ==> 3
SUM OF FIRST THREE TERM ==> 3/2 [2(2) + (3-1)3 ]
===> 3/2 [4 + 6]
==> 3/2 * 10
==> 15
ANSWER = 15
OR
A1 = 2(1)+1 ==> 3
A2 = 2(2)+1 ==> 5
A3= 2(3)+1 ==> 7
SO, A1+A2+A3 ==> 3+5+7 ==> 15
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