If the nth term of an ap is 2n+1 then the sum of its first three term is
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nth term = 2n+1
a1= 2+1=3
a2= 4+1=5
d = a2-a1
=5-3
=2
Sn = n/2 (2a+(n-1)d
S3 = 3/2 (6+2×2)
S3 =3/2(10)
S3 =3×5
S3 =15
so, the sum of the first three term is 15
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