if the nth term of an ap is (2n-1) then the sum of n term of an ap
Answers
The sum of n terms in an AP is given by
s= n/2(2a+(n-1)d)
where
s = sum of progression
n = number of terms
a = value of first term
d = difference between 2 terms
now, the first term in your question is 3 (2 x 1 + 1)
so, a = 3
second term is 5
third is 7, like that
so d = 2
Therefore, the sum of first n terms of the AP will be
n/2 [2 x 3 + (n-1) 2]
simplifying, we get the sum as
n [3+n-1]
n (n+2)
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commented Jul 5, 2018 by Bella cullen Basic (20 points)
not much helpful
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