if the nth term of an ap is 3n+2 then its 5th term is
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Step-by-step explanation:
so in this sum to find t5 ie 5th term of given ap
just substitute n as 5 in 3n+2
so hence
t5=3n+2
=(3×5)+2
=15+2
=17
t5=17
hence the 5th term of given ap is 17
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