if the nth term of an AP is (5n-3) find the sum of first 20 term of the AP using the formula
Answers
Answered by
58
Given:- nth term of ap=(5n-3)
Let's first take out the terms of the given ap.
So,
(5n-3)
For a1 put the value of n as '1'.
a1=5(1)-3=2
For a2 put the value of n as'2'.
a2= 5(2)-3=7
Now for common difference we have,
d=a2-a1
=7-2=5
Now we know the formula sn=n/2[2a+d]
A/q,
S20=20/2[2×2+19×5]
S20=10(4+25)
S20=990
Thus,the sum is 990.
Anonymous:
Bacchi's answer xD
Answered by
19
Explanation:
given
n th term = 5n-3
so, 1 St term = a= 5× 1-3(n=1)
=5-3
=2 ... #
2 nd term = 5× 2-3 ( n= 2)
= 10- 3
= 7...#
20th term °= 5×20 - 3 (n=20)
= 100- 3
= 97
## sum of 20 terms = n (a+l)/2
## n = no. of terms
a= 1st term
l = last term
20(2+97)/2
= 10× 99
= 990 (ans).
THERE CAN BE MISTAKE IN CALCULATION .
PLEASE CORRECT IT YOURSELF
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