If the nth term of an AP is 7−3n then find the sum of first twenty five terms.
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Answer:
An = 7-3n
A1 = 7-3(1)=4
A2= 7-3(2)=1
D = A2 + A1 = 1-4=-3
S25 = 25/2(2a + (n-1)D)
S25 = 25/2(2(4)+24(-3)
= 25/2(8-72)
= 25/2(-64)
= - 800
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