Question

If the nth term of an AP. is given by an = 6n-3, then the sum of first 10 terms if​

Answer 1

Answer:

300

Step-by-step explanation:

since sn=n/2[2a+ (n-1)*d]

and given an=6n-3

therefore a1= 6(1)-3=3

a2= 6(2)-3=9

d= a2-a1 = 9-3=6

s10 = 10/2[ 2 * 3 + (10-1)*6]= 300