if the nth term of an ap is n and the nth term is m, prove that its kth term is (m+n-k)
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am=a+(m−1)d=n
an=a+(n−1)d=m
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(m−n)d=n−m
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⇒d=−1
a+(1−m)=n
⇒a=m+n−1
p=a+(p−1)d
=m+n−1+1−p
ap=m+n−p
⇒( m+n-p)
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