Question

if the nth term of an AP is$\sqrt{2} ,\sqrt{8} ,\sqrt{18}$ is

Answer 1

Answer: $\sqrt{2n^{2} }$

Step-by-step explanation:

See the AP Clearly

$\sqrt{8} = 2\sqrt{2}$

$\sqrt{18} = 3\sqrt{2}$

So, the next terms are $4\sqrt{2} , 5\sqrt{2}$, ......, and so on.

So, nth term of AP is $n\sqrt{2} = \sqrt{2n^{2} }$