Question

If the nth term of an arithmetic progression is (5n-2) find its first term , common difference and 19th term

Answer 1

Answer :

Given that nth term of an Arithmetic progression,
tn = (5n - 2)

So, the first term,
t1 = (5 × 1) - 2

= 5 - 2

= 3

and

the second term,

t2 = (5 × 2) - 2

= 10 - 2

= 8

Hence, the common difference,

d = t2 - t1

= 8 - 3

= 5

∴ the 19th term of the Arithmetic progression,

t19

= t1 + (19 - 1)d

= 3 + (18 × 5)

= 3 + 90

= 93

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Answer 2

an= 5n-2
a1= 5(1)-2
a1=5+2=3

a2=5(2)-2= 10-2=8
D=a2-a1
D=8-3=5

a19=3+18d
a19=3+18(5)
a19=3+90=93