Question

If the nth term of an arithmetic progression
is an = 3n – 2, then find the 9th term.

Answer 1

Answer:

The nth term is given by 3n+2, so for the first term, this is when n=1, so we substitute 1 as n and do a similar thing for 2nd and 3rd terms. ...

The first term is when n= 1 3(1)+2 = 3+2 = 5 The second term is when n= 2 3(2)+2 = 6+2 = 8 The third term is when n=3 3(3)+2 = 11 The tenth term is when n=10 3(10)+2 = 30+2 = 32.