If the nth term of AP is (2n+1), find the sum of first n terms of the AP
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Answer:
an = 2n +1
Taking n= 1,2
a1 = 2×1 +1
= 2+1
= 3
a2 = 2×2+1
= 4+1
= 5
d = a2 - a1
= 5 - 3
= 2
Sn = n/2 ( 2a+(n-1) d)
= n/2 ( 2×3+(n-1)2)
= n/2 ( 6+2n-2)
= n/2 (4+2n)
= 2n+n sq.
Okay
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