if the nth term of the AP 9, 7, 5... is same as the nth term of thr AP 15, 12, 9.... ; find n
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In the 1st series 1st term a=9
common difference d=7-9= -2
nth term=a+(n-1)d
=9+(n-1).(-2)
=9-2n+2
=11-2n
In the 2nd series 1 st term a =15
common difference d=12-15= -3
nth term =a+(n-1) .d
=15+(n-1).(-3)
=15-3n+3
=18-3n
according to question
11 -2n= 18-3n
=> -2n+3n=18-11
=> n=7
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