Question

if the nth term of the AP is (2n+1).find Sn.​

Answer 1

Answer:

Tn = 2n+1

T1 = 2(1)+1 = 3

T2 = 2(2)+1 =5

D = T2 - T1

= 5 - 3

= 2

Sn = n/2 [2a+(n-1)d]

= n/2 [6 + (n-1)2]

= n/2 (6 + 2n - 2)

= n/2 (4+2n)

= n (2+n)

= 2n+n²

Thank you

Answer 2

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