Question

If the nth terms of two A.P.s 23, 25, 27, ... and 5,8,11,14...are equal then find the value of n ​

Answer 1

Answer:

Step-by-step explanation:

Formula for finding is a+(n-1)d

As they are equal put the values in formula

23+2n-2 = 5+3n-3

21+2n=2+3n

n=19

Answer 2

value of n = 19

first AP⇒ 23, 25, 27, .....

first term, a = 23 and common difference,d = 2

so, nth term , Tn = a + (n - 1)d

= 23 + (n - 1) × 2 = 23 + 2n - 2 = 21 + 2n ......(1)

2nd AP ⇒5, 8, 11, 14 ........

first term, a = 5 and common difference, d = 3

nth term, T'n = a + (n - 1)d

= 5 + (n - 1) × 3

= 5 + 3n - 3 = 2 + 3n ...........(2)

from equations (1) and (2) we get,

21 + 2n = 2 + 3n

⇒21 - 2 = 3n - 2n

⇒n = 19

also read similar questions : For what value of n, the nth term of the following two A.P.s are equal?

23, 25, 27, 29,...................... and -17, ...

https://brainly.in/question/2704937

The first term of two A.P.s are equal and the ratios of their common difference is 1 : 2 . If he 7th term of the first A...

https://brainly.in/question/15810037