Question

If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is​

Answer 1

Answer:

b can be 5 or 0 so first add them all its 20+a+b right but we need it to be divisible by 3 so but a as 1 and b as 0 so u got the sum as 21 which says that it is divisible by 3 and as b is 0 so it will be divisible by 5 too mark me as brainliest :)

Step-by-step explanation:

Answer 2

(d) 15. A number is divisible by 5 if its last digit is either 0 or 5 out of which 5 is maximum. So, we can add maximum 8 to 25 which will give us 33 which is divisible by 3. Hence, the correct answer is option (b).

hope its helpful :-[