If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is
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Answered by
1
Answer:
Khdlliyslushd
Step-by-step explanation:
Jr kya khsjskhdlhoiddkhddpyuelgfljdek
Answered by
0
Answer:
16
Step-by-step explanation:
We know,
If the sum of digits of a number is divisible by 3 then the number is divisible by 3
So,
2+3+4+5+(7) = 21
6+0+9 = 15
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