Question

If the number 2345p60q is exactly divisible by 3 and 5 then maximum value of p + q is
(A) 13
(C) 11
(B) 10
(D) 12​

Answer 1

Answer:

(A) 13

Step-by-step explanation:

q= 0 or 5

but q has to 5, because p+q

sum of degits of

2345p60q

is divisible by 3. Find p, when q= 5

Answer 2

Answer:

The minimum value of p+q is 13.

Step-by-step explanation:

We have a number 2345p60q which is exactly divisible by 3 and 5

We have to find the maximum value of p+q

To find that first we have to find the value of p and q

We know that if a number is divisible by 5 then the number should have a end digit 0 and 5

So the possible value of q can be only 0 and 5

We have to find the maximum value of p+q

So let us consider q=5 as we cannot consider q=0 to get a maximum value

Now substitute the q value in the given number

We get 2345p605

We have

2+3+4+5+p+6+0+5

25+p

Therefore a number greater than 25 and divisible by 27, 30

Hence p may be 2, 5, 8  

Here highest number=8

Therefore we have p=8 q=5

Hence p+q=8+5=13