Question

if the number 32a5 is divisible by 3 , then what could be the possible value of digit (a)...???? ​

Answer 1

ANSWER

The sum of digits of a number divisible by 3 is a multiple of 3

3+5+a+6+4=3n

18+a=3n

If n=6⇒3n=18

If n=9,3n=27

If n=6,7,8,9⇒18+a=18,21,24,27

∴a=0,3,6,9