if the number 3422213xy is divisible by99.find the values of x and y?
charugoyal:
is there anyone who could solve this out for me?
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if we devide 3422213 by 99 then the remainder is 75. if we x=2 and y=4, then the whole no. is devided by 99.
??
same, if we devide 3422213 by 99 then the remainder is 80. if we replace xy by19 then the whole no. is devided
bt how do we know that these are the values to be used
quient is 3456781
ok
but i still didnt get what r u trying to explain
we see the remainder is 80. now see the lest no. 0 put on 80, then the new no. is 800, now we see 99×8 =792 nd the reamaider is 8. now if we put any no. in the plce of y, nvr be remndr is zero. now again we put 1 in the plce of zero then take same process nd see the remainder is 9. now here if we put only 9 in the plce of y, then the no. is devided. if we any other no. then nvr be the remaider is zero
ok
kk thanks
my eng is not gud, try to understand
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