If the number 357A25B is divisible by 9 and 5, then (A+B) x AB = ??
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Answer:
by divisiblity test
A=0 and B=5
therefore and is 0
Answered by
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HEY MATE
357A25B
B is either 5 or 0 because when a number is divisible by 5 the last digit should be either 5 or 0
condition 1:
B=5
3+5+7+A+2+5+5=22+A
22+5=27(divisible by 9)
condition 2:
B=0
3+5+7+A+2+5+0=27+A
27+0=27(divisible by 9)
A=5;B=0
(A+B)AB= (5+0)5×0
= 5×0=0
HENCE VERIFIED
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