Question

If the number 497A is divisible by 3 and the number 562B is divisible by 4 the number of possible ordered pairs (A,B) is [Where A,B are digits]​

Answer 1

Step-by-step explanation:

so you must know how a no. is divisible by 3, so

4+9+7=20 and 20 isn't divisible by 3, so

497×2 (not)

497*3= 1491 and it is divisible by 3.

so, a=3

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and you too must know divisibility by 4

in 562, 62 isn't divisible by 4. so,

562*2=1124 and 24 is divisible by 4 so 1124 is too divisible by 4. so, b=2

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note= divisibility by 3 = if sum of all digits in number is divisible by 3 so the number is also divisible.

divisibility by 4= if the last 2 digits are divisible by 4 so the number is also divisible by 4.

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