Question

If the number 526x243 is completely divisible by 3 then the smallest whole number in place of x would be

Answer 1

Answer:

The divisibility test of 3 states that the sum of digits of a number should be completely divisible by 3.

5+2+6+x+2+4+3

22+x

The nearest multiple of 3 near 22 is 24.

X= 2

Answer 2

Answer:

If the number 526x243 is completely divisible by 3 then the smallest whole number in place of x would be 2.

This is because a number is divisible by 3 if the sum of its number is divisible by 3.

Eg: 21

   = 2 + 1

   = 3

3 is divisible by 3. ∴ 21 is divisible by 3

Similarily to find the smallest whole number in place of x which would make the number 526x243 divisible by three, we must add all the numbers in 526x243.

5 + 2 + 6 + x + 2 + 4 + 3

= 22 + x

As we know 24 is divisible by 3 and is the nearest multiple of 3 here.

So x can be 2 so that when 22 and 2 are added we get 24.

22 + x

= 22 + 2

= 24

∴ The smallest whole number in place of x is 2