Question

If the number 526x243 is completely divisible by 3 then the smallest whole number of place of x would be

Answer 1

Answer:

Divisibility Rule of 3 = Sum of all the digits must be divisible by 3

Eg:- 21    2 + 1 = 3

In this case

526x243... 5 + 2 + 6 + 2 + 4 + 3 = 22

The nearest number in front of 22 which is divisible by 3 = 24

24 - 22 = 2

Hence x = 2

5 + 2 + 6 + 2 + 2 + 4 + 3 = 24

Hope it helps

Answer 2

Answer:

x would be 2, 5 or 8

Step-by-step explanation:

Divisibility rule of 3

Adding all the digits should be divisible by 3

So 5+2+6+2+4+3 = 22 (excluding x )

We should add the digits to 24,27 or 30 to be divisible

Therefore x can be 2,5 or 8

Please mark me as the brainliest answer

Thank you ☺