If the number 61z5 is divisible by 3 then what are values z can take ?
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Answer:
to make the no. divisible by 3 sum of digits must be divisible by 3.
6+1+5 = 12
So z can take values 0 , 3 , 6 , 9
12+0 = 12
12+3= 15
12+6 = 18
12+ 9 = 21
all the no. are divisible by 3
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