Math, asked by syounusbasha, 9 months ago

If the number 88200
can be poime factorised as
2^3 x 3^2x5² x k², then the value of k is

Answers

Answered by Sakshisingh027

Answer:

Given that

The prime factorization of the given natural number n is 2^3× 3^2×5^2× 7

Prime factorization: by using prime factorization we can find out which prime numbers multiple together to make the original number.

To find the consecutive zeroes in a number, split out the 2’s and 5’s which can finally sum up together to give 10.

Thus, in the given natural number 'n' there are 2 consecutive zeroes.

Step-by-step explanation:

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