Question

if the number a b c d re form an AP then find the value of a-4b+6c-4d+e= ?​

Answer 1

Answer:

0

Step-by-step explanation:

The AP is : a  b  c  d  e

Let the first term be of the form A ; and the difference is D . Then

Let the AP be in the form :-

A-2D (a)   A-D(b)   A(c)   A+D(d)   A+2D(e)

Now using these terms in the value

a-4b+6c-4d+e

=A-2D-4(A-D)+6(A)-4(A+D)+(A+2D)

After expanding , we get

=A-4A+6A-4A+A

=2A-8A+6A

=8A-8A

=0

Answer 2

Answer: 0

Step-by-step explanation:

This question can be done in two steps

Assume the numbers to be 1,2,3,4,5

These 5 numbers are in AP

SO

a-4b+6c-4d+e

1-8+18-16+5=0