Question

If the number are x-1, x+2,x-7 are in a.p then find the value of x
Plzzz answer the question

Answer 1

AS WE KNOW THAT THE COMMON DIFFERENCE IS EQUAL , SO ......

(x+2)-(x-1)=(x-7)-(x+2) ...solve this equation nd u will get ur ans.

Answer 2

Answer:

There is no any real values of x for which the numbers are in AP.

Step-by-step explanation:

The numbers x-1, x+2,x-7 are in a.p.

In case of arithmetic sequence, the difference between two consecutive terms should be equal. We call this the "common difference" of an AP.

Since, the given numbers are in AP hence, we can write the equation on the basis of above mentioned concepts.

$x+2-(x-1)=x-7-(x+2)$

Distribute the negative over the parenthesis

$x+2-x+1=x-7-x-2$

Now, we can easily simplify the equation

$3=-9$

This statement is false because 3 is not equal to -9.

Hence, there is no solution for the equation.

Therefore, there is no any real values of x for which the numbers are in AP.