Question

if the number n-2,4n-1, and 5n+2 are in A.P. then find the value of n​

Answer 1

Answer:

n=1

Step-by-step explanation:

first term  = n - 2

second term  = 4n - 1

third term = 5n + 2

If it is in A.P,

d1 = t2 - t1

  = 4n - 1 - (n - 2)

   = 4n - 1 - n +2

   =4n -n -1 +2

   =3n + 1

d2 = t3 - t2

    = 5n + 2 - (4n - 1)

    = 5n + 2 - 4n + 1

    = 5n - 4n + 3

     = n + 3

d1 = d2

3n + 1 = n + 3

3n - n + 1 -3 = 0

2n - 2 =0

2n = 2

n = 2/2

n = 1